-32=(-2z+3+5)

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Solution for -32=(-2z+3+5) equation: 



-32=(-2z+3+5)

We move all terms to the left:

-32-((-2z+3+5))=0

We add all the numbers together, and all the variables

-((-2z+8))-32=0



We calculate terms in parentheses: -((-2z+8)), so:

(-2z+8)

We get rid of parentheses

-2z+8

Back to the equation:

-(-2z+8)



We get rid of parentheses

2z-8-32=0

We add all the numbers together, and all the variables

2z-40=0

We move all terms containing z to the left, all other terms to the right

2z=40

z=40/2

z=20

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