-32=-6(5b+1)-2(b-3)

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Solution for -32=-6(5b+1)-2(b-3) equation: 



-32=-6(5b+1)-2(b-3)

We move all terms to the left:

-32-(-6(5b+1)-2(b-3))=0



We calculate terms in parentheses: -(-6(5b+1)-2(b-3)), so:

-6(5b+1)-2(b-3)

We multiply parentheses

-30b-2b-6+6

We add all the numbers together, and all the variables

-32b

Back to the equation:

-(-32b)



We get rid of parentheses

32b-32=0

We move all terms containing b to the left, all other terms to the right

32b=32

b=32/32

b=1

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