-32=3+4(f-5)

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Solution for -32=3+4(f-5) equation: 



-32=3+4(f-5)

We move all terms to the left:

-32-(3+4(f-5))=0



We calculate terms in parentheses: -(3+4(f-5)), so:

3+4(f-5)

determiningTheFunctionDomain
4(f-5)+3

We multiply parentheses

4f-20+3

We add all the numbers together, and all the variables

4f-17

Back to the equation:

-(4f-17)



We get rid of parentheses

-4f+17-32=0

We add all the numbers together, and all the variables

-4f-15=0

We move all terms containing f to the left, all other terms to the right

-4f=15

f=15/-4

f=-3+3/4

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