-32=3+49(d-5)

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Solution for -32=3+49(d-5) equation: 



-32=3+49(d-5)

We move all terms to the left:

-32-(3+49(d-5))=0



We calculate terms in parentheses: -(3+49(d-5)), so:

3+49(d-5)

determiningTheFunctionDomain
49(d-5)+3

We multiply parentheses

49d-245+3

We add all the numbers together, and all the variables

49d-242

Back to the equation:

-(49d-242)



We get rid of parentheses

-49d+242-32=0

We add all the numbers together, and all the variables

-49d+210=0

We move all terms containing d to the left, all other terms to the right

-49d=-210

d=-210/-49

d=4+2/7

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