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-32x^2+30=0
a = -32; b = 0; c = +30;
Δ = b2-4ac
Δ = 02-4·(-32)·30
Δ = 3840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3840}=\sqrt{256*15}=\sqrt{256}*\sqrt{15}=16\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{15}}{2*-32}=\frac{0-16\sqrt{15}}{-64} =-\frac{16\sqrt{15}}{-64} =-\frac{\sqrt{15}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{15}}{2*-32}=\frac{0+16\sqrt{15}}{-64} =\frac{16\sqrt{15}}{-64} =\frac{\sqrt{15}}{-4} $
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