-32z+17=53-36z

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Solution for -32z+17=53-36z equation: 



-32z+17=53-36z

We move all terms to the left:

-32z+17-(53-36z)=0

We add all the numbers together, and all the variables

-32z-(-36z+53)+17=0

We get rid of parentheses

-32z+36z-53+17=0

We add all the numbers together, and all the variables

4z-36=0

We move all terms containing z to the left, all other terms to the right

4z=36

z=36/4

z=9

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