-33=-3(2r+2)-3r

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Solution for -33=-3(2r+2)-3r equation:



-33=-3(2r+2)-3r
We move all terms to the left:
-33-(-3(2r+2)-3r)=0
We calculate terms in parentheses: -(-3(2r+2)-3r), so:
-3(2r+2)-3r
We add all the numbers together, and all the variables
-3r-3(2r+2)
We multiply parentheses
-3r-6r-6
We add all the numbers together, and all the variables
-9r-6
Back to the equation:
-(-9r-6)
We get rid of parentheses
9r+6-33=0
We add all the numbers together, and all the variables
9r-27=0
We move all terms containing r to the left, all other terms to the right
9r=27
r=27/9
r=3

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