-33=-6y+3(y-2)

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Solution for -33=-6y+3(y-2) equation: 



-33=-6y+3(y-2)

We move all terms to the left:

-33-(-6y+3(y-2))=0



We calculate terms in parentheses: -(-6y+3(y-2)), so:

-6y+3(y-2)

We multiply parentheses

-6y+3y-6

We add all the numbers together, and all the variables

-3y-6

Back to the equation:

-(-3y-6)



We get rid of parentheses

3y+6-33=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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