-33=1/5(45-5y)

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Solution for -33=1/5(45-5y) equation: 



-33=1/5(45-5y)

We move all terms to the left:

-33-(1/5(45-5y))=0



Domain of the equation: 5(45-5y))!=0

y∈R



We add all the numbers together, and all the variables

-(1/5(-5y+45))-33=0

We multiply all the terms by the denominator


-(1-33*5(-5y+45))=0



We calculate terms in parentheses: -(1-33*5(-5y+45)), so:

1-33*5(-5y+45)

determiningTheFunctionDomain
-33*5(-5y+45)+1

Wy multiply elements

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We use the square of the difference formula

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Back to the equation:

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