-33=3(7-4b)+2(3-4b)

Solution for -33=3(7-4b)+2(3-4b) equation:

-33=3(7-4b)+2(3-4b)

We move all terms to the left:

-33-(3(7-4b)+2(3-4b))=0

We add all the numbers together, and all the variables

-(3(-4b+7)+2(-4b+3))-33=0


We calculate terms in parentheses: -(3(-4b+7)+2(-4b+3)), so:

3(-4b+7)+2(-4b+3)

We multiply parentheses

-12b-8b+21+6

We add all the numbers together, and all the variables

-20b+27

Back to the equation:

-(-20b+27)


We get rid of parentheses

20b-27-33=0

We add all the numbers together, and all the variables

20b-60=0

We move all terms containing b to the left, all other terms to the right

20b=60

b=60/20

b=3