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-33=9+2(n+5)
We move all terms to the left:
-33-(9+2(n+5))=0
We calculate terms in parentheses: -(9+2(n+5)), so:We get rid of parentheses
9+2(n+5)
determiningTheFunctionDomain 2(n+5)+9
We multiply parentheses
2n+10+9
We add all the numbers together, and all the variables
2n+19
Back to the equation:
-(2n+19)
-2n-19-33=0
We add all the numbers together, and all the variables
-2n-52=0
We move all terms containing n to the left, all other terms to the right
-2n=52
n=52/-2
n=-26
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