-35+2v=3(2v-1)

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Solution for -35+2v=3(2v-1) equation:



-35+2v=3(2v-1)
We move all terms to the left:
-35+2v-(3(2v-1))=0
We calculate terms in parentheses: -(3(2v-1)), so:
3(2v-1)
We multiply parentheses
6v-3
Back to the equation:
-(6v-3)
We get rid of parentheses
2v-6v+3-35=0
We add all the numbers together, and all the variables
-4v-32=0
We move all terms containing v to the left, all other terms to the right
-4v=32
v=32/-4
v=-8

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