-35/5=2x+4/3x

Solution for -35/5=2x+4/3x equation:

-35/5=2x+4/3x

We move all terms to the left:

-35/5-(2x+4/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+2x+4/3x)-35/5=0

We add all the numbers together, and all the variables

-(+2x+4/3x)-7=0

We get rid of parentheses

-2x-4/3x-7=0

We multiply all the terms by the denominator


-2x*3x-7*3x-4=0

Wy multiply elements

-6x^2-21x-4=0

a = -6; b = -21; c = -4;
Δ = b2-4ac
Δ = -212-4·(-6)·(-4)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{345}}{2*-6}=\frac{21-\sqrt{345}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{345}}{2*-6}=\frac{21+\sqrt{345}}{-12}
$