-35=1-2(4+7v)

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Solution for -35=1-2(4+7v) equation: 



-35=1-2(4+7v)

We move all terms to the left:

-35-(1-2(4+7v))=0

We add all the numbers together, and all the variables

-(1-2(7v+4))-35=0



We calculate terms in parentheses: -(1-2(7v+4)), so:

1-2(7v+4)

determiningTheFunctionDomain
-2(7v+4)+1

We multiply parentheses

-14v-8+1

We add all the numbers together, and all the variables

-14v-7

Back to the equation:

-(-14v-7)



We get rid of parentheses

14v+7-35=0

We add all the numbers together, and all the variables

14v-28=0

We move all terms containing v to the left, all other terms to the right

14v=28

v=28/14

v=2

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