-35=4(y-2)+5y

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Solution for -35=4(y-2)+5y equation: 



-35=4(y-2)+5y

We move all terms to the left:

-35-(4(y-2)+5y)=0



We calculate terms in parentheses: -(4(y-2)+5y), so:

4(y-2)+5y

We add all the numbers together, and all the variables

5y+4(y-2)

We multiply parentheses

5y+4y-8

We add all the numbers together, and all the variables

9y-8

Back to the equation:

-(9y-8)



We get rid of parentheses

-9y+8-35=0

We add all the numbers together, and all the variables

-9y-27=0

We move all terms containing y to the left, all other terms to the right

-9y=27

y=27/-9

y=-3

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