-35=4(y-2)+5y

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Solution for -35=4(y-2)+5y equation:



-35=4(y-2)+5y
We move all terms to the left:
-35-(4(y-2)+5y)=0
We calculate terms in parentheses: -(4(y-2)+5y), so:
4(y-2)+5y
We add all the numbers together, and all the variables
5y+4(y-2)
We multiply parentheses
5y+4y-8
We add all the numbers together, and all the variables
9y-8
Back to the equation:
-(9y-8)
We get rid of parentheses
-9y+8-35=0
We add all the numbers together, and all the variables
-9y-27=0
We move all terms containing y to the left, all other terms to the right
-9y=27
y=27/-9
y=-3

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