-35=x+4x+10(x+1)-2x-(x-1)

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Solution for -35=x+4x+10(x+1)-2x-(x-1) equation: 



-35=x+4x+10(x+1)-2x-(x-1)

We move all terms to the left:

-35-(x+4x+10(x+1)-2x-(x-1))=0



We calculate terms in parentheses: -(x+4x+10(x+1)-2x-(x-1)), so:

x+4x+10(x+1)-2x-(x-1)

We add all the numbers together, and all the variables

3x+10(x+1)-(x-1)

We multiply parentheses

3x+10x-(x-1)+10

We get rid of parentheses

3x+10x-x+1+10

We add all the numbers together, and all the variables

12x+11

Back to the equation:

-(12x+11)



We get rid of parentheses

-12x-11-35=0

We add all the numbers together, and all the variables

-12x-46=0

We move all terms containing x to the left, all other terms to the right

-12x=46

x=46/-12

x=-3+5/6

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