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-35x^2+245x+280=0
a = -35; b = 245; c = +280;
Δ = b2-4ac
Δ = 2452-4·(-35)·280
Δ = 99225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{99225}=315$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(245)-315}{2*-35}=\frac{-560}{-70} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(245)+315}{2*-35}=\frac{70}{-70} =-1 $
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