-35x2-5x+40=0

Solution for -35x2-5x+40=0 equation:

-35x^2-5x+40=0

a = -35; b = -5; c = +40;
Δ = b2-4ac
Δ = -52-4·(-35)·40
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-75}{2*-35}=\frac{-70}{-70}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+75}{2*-35}=\frac{80}{-70}
=-1+1/7
$