-36+12d=2(d-3)+22

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Solution for -36+12d=2(d-3)+22 equation: 



-36+12d=2(d-3)+22

We move all terms to the left:

-36+12d-(2(d-3)+22)=0



We calculate terms in parentheses: -(2(d-3)+22), so:

2(d-3)+22

We multiply parentheses

2d-6+22

We add all the numbers together, and all the variables

2d+16

Back to the equation:

-(2d+16)



We get rid of parentheses

12d-2d-16-36=0

We add all the numbers together, and all the variables

10d-52=0

We move all terms containing d to the left, all other terms to the right

10d=52

d=52/10

d=5+1/5

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