-36-3b=3(b+2)

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Solution for -36-3b=3(b+2) equation: 



-36-3b=3(b+2)

We move all terms to the left:

-36-3b-(3(b+2))=0



We calculate terms in parentheses: -(3(b+2)), so:

3(b+2)

We multiply parentheses

3b+6

Back to the equation:

-(3b+6)



We get rid of parentheses

-3b-3b-6-36=0

We add all the numbers together, and all the variables

-6b-42=0

We move all terms containing b to the left, all other terms to the right

-6b=42

b=42/-6

b=-7

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