-36a2+36a-8=0

Solution for -36a2+36a-8=0 equation:

-36a^2+36a-8=0

a = -36; b = 36; c = -8;
Δ = b2-4ac
Δ = 362-4·(-36)·(-8)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12}{2*-36}=\frac{-48}{-72}
=2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12}{2*-36}=\frac{-24}{-72}
=1/3
$