-37+3b=2-3(1-3b)

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Solution for -37+3b=2-3(1-3b) equation:



-37+3b=2-3(1-3b)
We move all terms to the left:
-37+3b-(2-3(1-3b))=0
We add all the numbers together, and all the variables
3b-(2-3(-3b+1))-37=0
We calculate terms in parentheses: -(2-3(-3b+1)), so:
2-3(-3b+1)
determiningTheFunctionDomain -3(-3b+1)+2
We multiply parentheses
9b-3+2
We add all the numbers together, and all the variables
9b-1
Back to the equation:
-(9b-1)
We get rid of parentheses
3b-9b+1-37=0
We add all the numbers together, and all the variables
-6b-36=0
We move all terms containing b to the left, all other terms to the right
-6b=36
b=36/-6
b=-6

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