If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-37-11x=5x-3x^2-2
We move all terms to the left:
-37-11x-(5x-3x^2-2)=0
We get rid of parentheses
3x^2-5x-11x+2-37=0
We add all the numbers together, and all the variables
3x^2-16x-35=0
a = 3; b = -16; c = -35;
Δ = b2-4ac
Δ = -162-4·3·(-35)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-26}{2*3}=\frac{-10}{6} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+26}{2*3}=\frac{42}{6} =7 $
| 39=7-10x+14x | | |2x-3+4=17 | | x-0.1x=99 | | 4x=2x+36-4 | | 5g(4+4)=8 | | 6x/2=3 | | X2-4x-221=0 | | 2x+40+8=10x | | 3/4k+16=2-1/8 | | 3x+60-15=8x | | v2=-42+13v | | 81=15x-7x-7 | | 49a2-115a-147=4a-7a2 | | 3y+5-2=11 | | 2m+3=2m+7 | | 140+16c=220 | | 11(k-1)=7(k-35) | | 140c+16=220 | | x/x+5+5/x+5+4=0 | | 140+16=220c | | 6x-8=8-6 | | (v/v+2)^2-(11v/v+2)=-30 | | y/2=y+3/2 | | 11=f/9 | | x2+10=-7x | | (3x+7)+(3x+6)+(3x)=(3x)+(3x)+(4x+7) | | 3(y-10)+1=-2(y-16) | | 7x=2x+33-6x | | m2-32=4m | | 9f+5(-8f+1)=3f+7-10f | | 2(2x-6)=6x-4 | | -x=2x-35-25 |