-37=3(3x+5)+5(1+2x)

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Solution for -37=3(3x+5)+5(1+2x) equation: 



-37=3(3x+5)+5(1+2x)

We move all terms to the left:

-37-(3(3x+5)+5(1+2x))=0

We add all the numbers together, and all the variables

-(3(3x+5)+5(2x+1))-37=0



We calculate terms in parentheses: -(3(3x+5)+5(2x+1)), so:

3(3x+5)+5(2x+1)

We multiply parentheses

9x+10x+15+5

We add all the numbers together, and all the variables

19x+20

Back to the equation:

-(19x+20)



We get rid of parentheses

-19x-20-37=0

We add all the numbers together, and all the variables

-19x-57=0

We move all terms containing x to the left, all other terms to the right

-19x=57

x=57/-19

x=-3

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