-38(-6-2y)=12(2y-3)-1

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Solution for -38(-6-2y)=12(2y-3)-1 equation: 



-38(-6-2y)=12(2y-3)-1

We move all terms to the left:

-38(-6-2y)-(12(2y-3)-1)=0

We add all the numbers together, and all the variables

-38(-2y-6)-(12(2y-3)-1)=0

We multiply parentheses

76y-(12(2y-3)-1)+228=0



We calculate terms in parentheses: -(12(2y-3)-1), so:

12(2y-3)-1

We multiply parentheses

24y-36-1

We add all the numbers together, and all the variables

24y-37

Back to the equation:

-(24y-37)



We get rid of parentheses

76y-24y+37+228=0

We add all the numbers together, and all the variables

52y+265=0

We move all terms containing y to the left, all other terms to the right

52y=-265

y=-265/52

y=-5+5/52

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