-38=2(2x-4)+10

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Solution for -38=2(2x-4)+10 equation: 



-38=2(2x-4)+10

We move all terms to the left:

-38-(2(2x-4)+10)=0



We calculate terms in parentheses: -(2(2x-4)+10), so:

2(2x-4)+10

We multiply parentheses

4x-8+10

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

-4x-2-38=0

We add all the numbers together, and all the variables

-4x-40=0

We move all terms containing x to the left, all other terms to the right

-4x=40

x=40/-4

x=-10

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