-38=2(y-5)+5y

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Solution for -38=2(y-5)+5y equation: 



-38=2(y-5)+5y

We move all terms to the left:

-38-(2(y-5)+5y)=0



We calculate terms in parentheses: -(2(y-5)+5y), so:

2(y-5)+5y

We add all the numbers together, and all the variables

5y+2(y-5)

We multiply parentheses

5y+2y-10

We add all the numbers together, and all the variables

7y-10

Back to the equation:

-(7y-10)



We get rid of parentheses

-7y+10-38=0

We add all the numbers together, and all the variables

-7y-28=0

We move all terms containing y to the left, all other terms to the right

-7y=28

y=28/-7

y=-4

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