-39(b-8)-5=9(b+2)+1

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Solution for -39(b-8)-5=9(b+2)+1 equation: 



-39(b-8)-5=9(b+2)+1

We move all terms to the left:

-39(b-8)-5-(9(b+2)+1)=0

We multiply parentheses

-39b-(9(b+2)+1)+312-5=0



We calculate terms in parentheses: -(9(b+2)+1), so:

9(b+2)+1

We multiply parentheses

9b+18+1

We add all the numbers together, and all the variables

9b+19

Back to the equation:

-(9b+19)



We add all the numbers together, and all the variables

-39b-(9b+19)+307=0

We get rid of parentheses

-39b-9b-19+307=0

We add all the numbers together, and all the variables

-48b+288=0

We move all terms containing b to the left, all other terms to the right

-48b=-288

b=-288/-48

b=+6

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