-39+3v=1+2(6v+7)

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Solution for -39+3v=1+2(6v+7) equation: 



-39+3v=1+2(6v+7)

We move all terms to the left:

-39+3v-(1+2(6v+7))=0



We calculate terms in parentheses: -(1+2(6v+7)), so:

1+2(6v+7)

determiningTheFunctionDomain
2(6v+7)+1

We multiply parentheses

12v+14+1

We add all the numbers together, and all the variables

12v+15

Back to the equation:

-(12v+15)



We get rid of parentheses

3v-12v-15-39=0

We add all the numbers together, and all the variables

-9v-54=0

We move all terms containing v to the left, all other terms to the right

-9v=54

v=54/-9

v=-6

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