-399=7(7q-3)+3q

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Solution for -399=7(7q-3)+3q equation: 



-399=7(7q-3)+3q

We move all terms to the left:

-399-(7(7q-3)+3q)=0



We calculate terms in parentheses: -(7(7q-3)+3q), so:

7(7q-3)+3q

We add all the numbers together, and all the variables

3q+7(7q-3)

We multiply parentheses

3q+49q-21

We add all the numbers together, and all the variables

52q-21

Back to the equation:

-(52q-21)



We get rid of parentheses

-52q+21-399=0

We add all the numbers together, and all the variables

-52q-378=0

We move all terms containing q to the left, all other terms to the right

-52q=378

q=378/-52

q=-7+7/26

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