-39=2(v-6)-5v

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Solution for -39=2(v-6)-5v equation: 



-39=2(v-6)-5v

We move all terms to the left:

-39-(2(v-6)-5v)=0



We calculate terms in parentheses: -(2(v-6)-5v), so:

2(v-6)-5v

We add all the numbers together, and all the variables

-5v+2(v-6)

We multiply parentheses

-5v+2v-12

We add all the numbers together, and all the variables

-3v-12

Back to the equation:

-(-3v-12)



We get rid of parentheses

3v+12-39=0

We add all the numbers together, and all the variables

3v-27=0

We move all terms containing v to the left, all other terms to the right

3v=27

v=27/3

v=9

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