-3=(-5/9)(5)+b

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Solution for -3=(-5/9)(5)+b equation: 



-3=(-5/9)(5)+b

We move all terms to the left:

-3-((-5/9)(5)+b)=0



Domain of the equation: 9)5+b)!=0

b!=0/1

b!=0

b∈R



We multiply all the terms by the denominator


-((-5-3*9)5+b)=0



We calculate terms in parentheses: -((-5-3*9)5+b), so:

(-5-3*9)5+b

determiningTheFunctionDomain
b+(-5-3*9)5

We add all the numbers together, and all the variables

b+(-32)5

We add all the numbers together, and all the variables

b-160

Back to the equation:

-(b-160)



We get rid of parentheses

-b+160=0

We add all the numbers together, and all the variables

-1b+160=0

We move all terms containing b to the left, all other terms to the right

-b=-160

b=-160/-1

b=+160

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