-3=(n+3)/2

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Solution for -3=(n+3)/2 equation: 



-3=(n+3)/2

We move all terms to the left:

-3-((n+3)/2)=0

We multiply all the terms by the denominator


-((n+3)-3*2)=0



We calculate terms in parentheses: -((n+3)-3*2), so:

(n+3)-3*2

We add all the numbers together, and all the variables

(n+3)-6

We get rid of parentheses

n+3-6

We add all the numbers together, and all the variables

n-3

Back to the equation:

-(n-3)



We get rid of parentheses

-n+3=0

We add all the numbers together, and all the variables

-1n+3=0

We move all terms containing n to the left, all other terms to the right

-n=-3

n=-3/-1

n=+3

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