-3=(x+1)(x-2)

Solution for -3=(x+1)(x-2) equation:

-3=(x+1)(x-2)

We move all terms to the left:

-3-((x+1)(x-2))=0

We multiply parentheses ..

-((+x^2-2x+x-2))-3=0


We calculate terms in parentheses: -((+x^2-2x+x-2)), so:

(+x^2-2x+x-2)

We get rid of parentheses

x^2-2x+x-2

We add all the numbers together, and all the variables

x^2-1x-2

Back to the equation:

-(x^2-1x-2)


We get rid of parentheses

-x^2+1x+2-3=0

We add all the numbers together, and all the variables

-1x^2+x-1=0

a = -1; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation