-3=(x+2)/6

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Solution for -3=(x+2)/6 equation: 



-3=(x+2)/6

We move all terms to the left:

-3-((x+2)/6)=0

We multiply all the terms by the denominator


-((x+2)-3*6)=0



We calculate terms in parentheses: -((x+2)-3*6), so:

(x+2)-3*6

We add all the numbers together, and all the variables

(x+2)-18

We get rid of parentheses

x+2-18

We add all the numbers together, and all the variables

x-16

Back to the equation:

-(x-16)



We get rid of parentheses

-x+16=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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