-3=(x+2x2+3x)

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Solution for -3=(x+2x2+3x) equation: 



-3=(x+2x^2+3x)

We move all terms to the left:

-3-((x+2x^2+3x))=0



We calculate terms in parentheses: -((x+2x^2+3x)), so:

(x+2x^2+3x)

We get rid of parentheses

2x^2+x+3x

We add all the numbers together, and all the variables

2x^2+4x

Back to the equation:

-(2x^2+4x)



We get rid of parentheses

-2x^2-4x-3=0

a = -2; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·(-2)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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