-3=(z/2)+2

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Solution for -3=(z/2)+2 equation:



-3=(z/2)+2
We move all terms to the left:
-3-((z/2)+2)=0
We add all the numbers together, and all the variables
-((+z/2)+2)-3=0
We multiply all the terms by the denominator
-((+z-3*2)+2)=0
We calculate terms in parentheses: -((+z-3*2)+2), so:
(+z-3*2)+2
We add all the numbers together, and all the variables
(z-6)+2
We get rid of parentheses
z-6+2
We add all the numbers together, and all the variables
z-4
Back to the equation:
-(z-4)
We get rid of parentheses
-z+4=0
We add all the numbers together, and all the variables
-1z+4=0
We move all terms containing z to the left, all other terms to the right
-z=-4
z=-4/-1
z=+4

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