-3=(z/2)+2

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Solution for -3=(z/2)+2 equation: 



-3=(z/2)+2

We move all terms to the left:

-3-((z/2)+2)=0

We add all the numbers together, and all the variables

-((+z/2)+2)-3=0

We multiply all the terms by the denominator


-((+z-3*2)+2)=0



We calculate terms in parentheses: -((+z-3*2)+2), so:

(+z-3*2)+2

We add all the numbers together, and all the variables

(z-6)+2

We get rid of parentheses

z-6+2

We add all the numbers together, and all the variables

z-4

Back to the equation:

-(z-4)



We get rid of parentheses

-z+4=0

We add all the numbers together, and all the variables

-1z+4=0

We move all terms containing z to the left, all other terms to the right

-z=-4

z=-4/-1

z=+4

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