-3=+6(z+2)=6-5z-1)-2

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Solution for -3=+6(z+2)=6-5z-1)-2 equation: 



-3=+6(z+2)=6-5z-1)-2

We move all terms to the left:

-3-(+6(z+2))=0



We calculate terms in parentheses: -(+6(z+2)), so:

+6(z+2)

determiningTheFunctionDomain
6(z+2)

We multiply parentheses

6z+12

Back to the equation:

-(6z+12)



We get rid of parentheses

-6z-12-3=0

We add all the numbers together, and all the variables

-6z-15=0

We move all terms containing z to the left, all other terms to the right

-6z=15

z=15/-6

z=-2+1/2

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