-3=-1/5(-5)+b

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Solution for -3=-1/5(-5)+b equation:



-3=-1/5(-5)+b
We move all terms to the left:
-3-(-1/5(-5)+b)=0
Domain of the equation: 5(-5)+b)!=0
b∈R
We multiply all the terms by the denominator
-(-1-3*5(-5)+b)=0
We calculate terms in parentheses: -(-1-3*5(-5)+b), so:
-1-3*5(-5)+b
determiningTheFunctionDomain b-1-3*5(-5)
We add all the numbers together, and all the variables
b+74
Back to the equation:
-(b+74)
We get rid of parentheses
-b-74=0
We add all the numbers together, and all the variables
-1b-74=0
We move all terms containing b to the left, all other terms to the right
-b=74
b=74/-1
b=-74

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