-3=-1/5(-5)+b

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Solution for -3=-1/5(-5)+b equation: 



-3=-1/5(-5)+b

We move all terms to the left:

-3-(-1/5(-5)+b)=0



Domain of the equation: 5(-5)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-1-3*5(-5)+b)=0



We calculate terms in parentheses: -(-1-3*5(-5)+b), so:

-1-3*5(-5)+b

determiningTheFunctionDomain
b-1-3*5(-5)

We add all the numbers together, and all the variables

b+74

Back to the equation:

-(b+74)



We get rid of parentheses

-b-74=0

We add all the numbers together, and all the variables

-1b-74=0

We move all terms containing b to the left, all other terms to the right

-b=74

b=74/-1

b=-74

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