-3=-15-2(c-1)3c

Solution for -3=-15-2(c-1)3c equation:

-3=-15-2(c-1)3c

We move all terms to the left:

-3-(-15-2(c-1)3c)=0


We calculate terms in parentheses: -(-15-2(c-1)3c), so:

-15-2(c-1)3c

determiningTheFunctionDomain
-2(c-1)3c-15

We multiply parentheses

-6c^2+6c-15

Back to the equation:

-(-6c^2+6c-15)


We get rid of parentheses

6c^2-6c+15-3=0

We add all the numbers together, and all the variables

6c^2-6c+12=0

a = 6; b = -6; c = +12;
Δ = b2-4ac
Δ = -62-4·6·12
Δ = -252
Delta is less than zero, so there is no solution for the equation