-3=-2/3*4+b

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Solution for -3=-2/3*4+b equation: 



-3=-2/3*4+b

We move all terms to the left:

-3-(-2/3*4+b)=0



Domain of the equation: 3*4+b)!=0

b∈R



We add all the numbers together, and all the variables

-(+b-2/3*4)-3=0

We get rid of parentheses

-b-3+2/3*4=0

We multiply all the terms by the denominator


-b*3*4+2-3*3*4=0

We add all the numbers together, and all the variables

-b*3*4-34=0

Wy multiply elements

-12b*4-34=0

Wy multiply elements

-48b-34=0

We move all terms containing b to the left, all other terms to the right

-48b=34

b=34/-48

b=-17/24

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