-3=-25-2(c+1)-3c

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Solution for -3=-25-2(c+1)-3c equation: 



-3=-25-2(c+1)-3c

We move all terms to the left:

-3-(-25-2(c+1)-3c)=0



We calculate terms in parentheses: -(-25-2(c+1)-3c), so:

-25-2(c+1)-3c

determiningTheFunctionDomain
-2(c+1)-3c-25

We add all the numbers together, and all the variables

-3c-2(c+1)-25

We multiply parentheses

-3c-2c-2-25

We add all the numbers together, and all the variables

-5c-27

Back to the equation:

-(-5c-27)



We get rid of parentheses

5c+27-3=0

We add all the numbers together, and all the variables

5c+24=0

We move all terms containing c to the left, all other terms to the right

5c=-24

c=-24/5

c=-4+4/5

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