-3=-3/5(-5)+b

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Solution for -3=-3/5(-5)+b equation: 



-3=-3/5(-5)+b

We move all terms to the left:

-3-(-3/5(-5)+b)=0



Domain of the equation: 5(-5)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-3-3*5(-5)+b)=0



We calculate terms in parentheses: -(-3-3*5(-5)+b), so:

-3-3*5(-5)+b

determiningTheFunctionDomain
b-3-3*5(-5)

We add all the numbers together, and all the variables

b+72

Back to the equation:

-(b+72)



We get rid of parentheses

-b-72=0

We add all the numbers together, and all the variables

-1b-72=0

We move all terms containing b to the left, all other terms to the right

-b=72

b=72/-1

b=-72

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