-3=-3/5(-5)-b

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Solution for -3=-3/5(-5)-b equation: 



-3=-3/5(-5)-b

We move all terms to the left:

-3-(-3/5(-5)-b)=0



Domain of the equation: 5(-5)-b)!=0

b∈R



We multiply all the terms by the denominator


-(-3-3*5(-5)-b)=0



We calculate terms in parentheses: -(-3-3*5(-5)-b), so:

-3-3*5(-5)-b

determiningTheFunctionDomain
-b-3-3*5(-5)

We add all the numbers together, and all the variables

-1b+72

Back to the equation:

-(-1b+72)



We get rid of parentheses

1b-72=0

We add all the numbers together, and all the variables

b-72=0

We move all terms containing b to the left, all other terms to the right

b=72

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