-3=1/2*3+b

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Solution for -3=1/2*3+b equation: 



-3=1/2*3+b

We move all terms to the left:

-3-(1/2*3+b)=0



Domain of the equation: 2*3+b)!=0

b∈R



We add all the numbers together, and all the variables

-(+b+1/2*3)-3=0

We get rid of parentheses

-b-3-1/2*3=0

We multiply all the terms by the denominator


-b*2*3-1-3*2*3=0

We add all the numbers together, and all the variables

-b*2*3-19=0

Wy multiply elements

-6b*3-19=0

Wy multiply elements

-18b-19=0

We move all terms containing b to the left, all other terms to the right

-18b=19

b=19/-18

b=-1+1/18

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