-3=12y+-5(2y+-7)

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Solution for -3=12y+-5(2y+-7) equation: 



-3=12y+-5(2y+-7)

We move all terms to the left:

-3-(12y+-5(2y+-7))=0

We add all the numbers together, and all the variables

-(12y+-5(2y-7))-3=0

We use the square of the difference formula

-(12y-5(2y-7))-3=0



We calculate terms in parentheses: -(12y-5(2y-7)), so:

12y-5(2y-7)

We multiply parentheses

12y-10y+35

We add all the numbers together, and all the variables

2y+35

Back to the equation:

-(2y+35)



We get rid of parentheses

-2y-35-3=0

We add all the numbers together, and all the variables

-2y-38=0

We move all terms containing y to the left, all other terms to the right

-2y=38

y=38/-2

y=-19

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