-3=12y-5)(2y-7

Solution for -3=12y-5)(2y-7 equation:

-3=12y-5)(2y-7

We move all terms to the left:

-3-(12y-5)(2y-7)=0

We multiply parentheses ..

-(+24y^2-84y-10y+35)-3=0

We get rid of parentheses

-24y^2+84y+10y-35-3=0

We add all the numbers together, and all the variables

-24y^2+94y-38=0

a = -24; b = 94; c = -38;
Δ = b2-4ac
Δ = 942-4·(-24)·(-38)
Δ = 5188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5188}=\sqrt{4*1297}=\sqrt{4}*\sqrt{1297}=2\sqrt{1297}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(94)-2\sqrt{1297}}{2*-24}=\frac{-94-2\sqrt{1297}}{-48}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(94)+2\sqrt{1297}}{2*-24}=\frac{-94+2\sqrt{1297}}{-48}
$