-3=2(3-b)-b

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Solution for -3=2(3-b)-b equation: 



-3=2(3-b)-b

We move all terms to the left:

-3-(2(3-b)-b)=0

We add all the numbers together, and all the variables

-(2(-1b+3)-b)-3=0



We calculate terms in parentheses: -(2(-1b+3)-b), so:

2(-1b+3)-b

We add all the numbers together, and all the variables

-1b+2(-1b+3)

We multiply parentheses

-1b-2b+6

We add all the numbers together, and all the variables

-3b+6

Back to the equation:

-(-3b+6)



We get rid of parentheses

3b-6-3=0

We add all the numbers together, and all the variables

3b-9=0

We move all terms containing b to the left, all other terms to the right

3b=9

b=9/3

b=3

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