-3=2(j+5)-7

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Solution for -3=2(j+5)-7 equation: 



-3=2(j+5)-7

We move all terms to the left:

-3-(2(j+5)-7)=0



We calculate terms in parentheses: -(2(j+5)-7), so:

2(j+5)-7

We multiply parentheses

2j+10-7

We add all the numbers together, and all the variables

2j+3

Back to the equation:

-(2j+3)



We get rid of parentheses

-2j-3-3=0

We add all the numbers together, and all the variables

-2j-6=0

We move all terms containing j to the left, all other terms to the right

-2j=6

j=6/-2

j=-3

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