-3=3(t-5)-t

Solution for -3=3(t-5)-t equation:

-3=3(t-5)-t

We move all terms to the left:

-3-(3(t-5)-t)=0


We calculate terms in parentheses: -(3(t-5)-t), so:

3(t-5)-t

We add all the numbers together, and all the variables

-1t+3(t-5)

We multiply parentheses

-1t+3t-15

We add all the numbers together, and all the variables

2t-15

Back to the equation:

-(2t-15)


We get rid of parentheses

-2t+15-3=0

We add all the numbers together, and all the variables

-2t+12=0

We move all terms containing t to the left, all other terms to the right

-2t=-12

t=-12/-2

t=+6